1-DAV-202 Data Management 2023/24
Previously 2-INF-185 Data Source Integration

Materials · Introduction · Rules · Contact
· Grades from marked homeworks are on the server in file /grades/userid.txt
· Dates of project submission and oral exams:
Early: submit project May 24 9:00am, oral exams May 27 1:00pm (limit 5 students).
Otherwise submit project June 11, 9:00am, oral exams June 18 and 21 (estimated 9:00am-1:00pm, schedule will be published before exam).
Sign up for one the exam days in AIS before June 11.
Remedial exams will take place in the last week of the exam period. Beware, there will not be much time to prepare a better project. Projects should be submitted as homeworks to /submit/project.
· Cloud homework is due on May 20 9:00am.


Difference between revisions of "HWr2"

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See also the [[Lr2|current]] and the [[Lr1|the previous]] lecture.
+
See also the [[Lr2|current]] and the [[Lr1|previous]] lecture.
  
 
* Do either tasks A,B,C (beginners) or B,C,D (more advanced). You can also do all four for bonus credit.
 
* Do either tasks A,B,C (beginners) or B,C,D (more advanced). You can also do all four for bonus credit.
Line 11: Line 11:
 
===Task A: sign test===
 
===Task A: sign test===
  
* Consider a situation in which players played ''n'' games, out of which a fraction of ''q'' were won by ''A'' (the example in the lecture corresponds to ''q=0.6'' and ''n=10'')
+
* Consider a situation in which players played ''n'' games, out of which a fraction of ''q'' were won by ''A'' (the example in the lecture corresponds to ''q=0.6'' and ''n=10'').
* Compute a table of p-values for ''n=10,20,...,90,100'' and for ''q=0.6, 0.7, 0.8, 0.9''
+
* Compute a table of p-values for combinations of ''n=10,20,...,90,100'' and ''q=0.6, 0.7, 0.8, 0.9''.
* Plot the table using <tt>matplot</tt> (''n'' is x-axis, one line for each value of ''q'')
+
* Plot the table using <tt>matplot</tt> (''n'' is x-axis, one line for each value of ''q'').
 
<!-- NOTEX -->
 
<!-- NOTEX -->
* '''Submit''' the plot in <tt>sign.png</tt>
+
* '''Submit''' the plot in <tt>sign.png</tt>.
* '''Discuss''' the values you have seen in the plot / table
+
* '''Discuss''' the values you see in the plot / table.
 
<!-- /NOTEX -->
 
<!-- /NOTEX -->
  
Line 22: Line 22:
 
<syntaxhighlight lang="r">
 
<syntaxhighlight lang="r">
 
# create vector rows with values 10,20,...,100
 
# create vector rows with values 10,20,...,100
rows=(1:10)*10
+
rows = (1:10) * 10
 
# create vector columns with required values of q
 
# create vector columns with required values of q
columns=c(0.6, 0.7, 0.8, 0.9)
+
columns = c(0.6, 0.7, 0.8, 0.9)
 
# create empty matrix of pvalues  
 
# create empty matrix of pvalues  
pvalues = matrix(0,length(rows),length(columns))
+
pvalues = matrix(0, length(rows), length(columns))
 
# TODO: fill in matrix pvalues using binom.test
 
# TODO: fill in matrix pvalues using binom.test
  
 
# set names of rows and columns
 
# set names of rows and columns
rownames(pvalues)=rows
+
rownames(pvalues) = rows
colnames(pvalues)=columns
+
colnames(pvalues) = columns
 
# careful: pvalues[10,] is now 10th row, i.e. value for n=100,  
 
# careful: pvalues[10,] is now 10th row, i.e. value for n=100,  
 
#          pvalues["10",] is the first row, i.e. value for n=10
 
#          pvalues["10",] is the first row, i.e. value for n=10
Line 39: Line 39:
  
 
# create x-axis matrix (as in HWr1, part D)
 
# create x-axis matrix (as in HWr1, part D)
x=matrix(rep(rows,length(columns)),nrow=length(rows))
+
x=matrix(rep(rows, length(columns)), nrow=length(rows))
 
# matplot command
 
# matplot command
 
png("sign.png")
 
png("sign.png")
matplot(x,pvalues,type="l",col=c(1:length(columns)),lty=1)
+
matplot(x, pvalues, type="l", col=c(1:length(columns)), lty=1)
legend("topright",legend=columns,col=c(1:length(columns)),lty=1)
+
legend("topright", legend=columns, col=c(1:length(columns)), lty=1)
 
dev.off()
 
dev.off()
 
</syntaxhighlight>
 
</syntaxhighlight>
Line 49: Line 49:
 
===Task B: Welch's t-test on microarray data===
 
===Task B: Welch's t-test on microarray data===
  
Read the microarray data, and preprocess them (last time we worked with preprocessed data). We first transform it to log scale  and then shift and scale values in each column so that median is 0 and sum of squares of values is 1. This makes values more comparable between experiments; in practice more elaborate normalization is often performed. In the rest, work with table ''a'' containing preprocessed data.
+
Run the code below which reads the microarray data and preprocesses them (the last time we worked with preprocessed data). We first transform it to log scale  and then shift and scale values in each column so that median is 0 and sum of squares of values is 1. This makes values more comparable between experiments; in practice more elaborate normalization is often performed. In the rest, work with table ''a'' containing preprocessed data.
 
<syntaxhighlight lang="r">
 
<syntaxhighlight lang="r">
 
# read the input file
 
# read the input file
Line 60: Line 60:
 
a = scale(input, center=med)
 
a = scale(input, center=med)
 
</syntaxhighlight>
 
</syntaxhighlight>
Columns 1,2,3 are reference, columns 4,5,6 acetic acid, 7,8,9 benzoate, 10,11,12 propionate, and 13,14,15 sorbate
+
Columns 1,2,3 are control, columns 4,5,6 acetic acid, 7,8,9 benzoate, 10,11,12 propionate, and 13,14,15 sorbate.
  
 
Write a function <tt>my.test</tt> which will take as arguments table ''a'' and 2 lists of columns (e.g. 1:3 and 4:6) and will run for each row of the table Welch's t-test of the first set of columns versus the second set. It will return the resulting vector of p-values, one for each gene.  
 
Write a function <tt>my.test</tt> which will take as arguments table ''a'' and 2 lists of columns (e.g. 1:3 and 4:6) and will run for each row of the table Welch's t-test of the first set of columns versus the second set. It will return the resulting vector of p-values, one for each gene.  
* For example by calling <tt>pa <- my.test(a, 1:3, 4:6)</tt> we will compute p-values for differences between reference and acetic acid (computation may take some time)
+
* For example by calling <tt>pb <- my.test(a, 1:3, 7:9)</tt> we will compute p-values for differences between control and benzoate (computation may take some time)
* The first 5 values of <tt>pa</tt> should be
+
* The first 5 values of <tt>pb</tt> should be
 
<pre>
 
<pre>
> pa[1:5]
+
> pb[1:5]
[1] 0.7696213 0.1606410 0.5288919 0.9919455 0.1580886
+
[1] 0.02358974 0.05503082 0.15354833 0.68060345 0.04637482
 
</pre>
 
</pre>
* Run the test for all four acids
+
* Run the test for all four acids.
* '''Report''' how many genes were significant with p-value at most 0.01 for each acid
+
* '''Report''' for each acid how many genes were significant with p-value at most 0.01.
** See [[HWr1#Vector_arithmetics|Vector arithmetics in HWr1]]
+
** See [[HWr1#Vector_arithmetic|Vector arithmetic in HWr1]]
** You can count <tt>TRUE</tt> items in a vector of booleans by <tt>sum</tt>, e.g. <tt>sum(TRUE,FALSE,TRUE)</tt> is 2
+
** You can count <tt>TRUE</tt> items in a vector of booleans by <tt>sum</tt>, e.g. <tt>sum(TRUE,FALSE,TRUE)</tt> is 2.
* '''Report''' how many genes are significant for both acetic and benzoate acids simultaneously (logical and is written as <tt>&</tt>).
+
* '''Report''' also how many genes are significant for both acetic and benzoate acids simultaneously (logical "and" is written as <tt>&</tt>).
  
 
===Task C: multiple testing correction===
 
===Task C: multiple testing correction===
  
Run the following snippet of code, which works on the vector of p-values <tt>pa</tt> obtained for acetate in task B
+
Run the following snippet of code, which works on the vector of p-values <tt>pb</tt> obtained for benzoate in task B.
 
<syntaxhighlight lang="r">
 
<syntaxhighlight lang="r">
# adjusts vectors of p-vales from tasks B for using Bonferroni correction
+
# adjusts vectors of p-values from tasks B for using Bonferroni correction
pa.adjusted = p.adjust(pa, method ="bonferroni")
+
pb.adjusted = p.adjust(pb, method ="bonferroni")
# add this adjusted vector to frame a
+
# add both p-value columns pb and pb.adjusted to frame a
a <-  cbind(a, pa.adjusted)
+
a <-  cbind(a, pb, pb.adjusted)
# create permutation ordered by pa.adjusted
+
# create permutation ordered by pb.adjusted
oa = order(pa.adjusted)
+
ob = order(pb.adjusted)
# select from table five rows with the lowest pa.adjusted (using vector oa)
+
# select from table five rows with the lowest pb.adjusted (using vector ob)
# and display columns containing reference, acetate and adjusted p-value
+
# and display columns containing control, benzoate and both original and adjusted p-value
a[oa[1:5],c(1:6,16)]
+
a[ob[1:5],c(1:3,7:9,16,17)]
 
</syntaxhighlight>
 
</syntaxhighlight>
  
 
You should get an output like this:
 
You should get an output like this:
 
<pre>
 
<pre>
            ref1    ref2    ref3 acetate1  acetate2 acetate3 pa.adjusted
+
      control1 control2  control3  benzoate1  benzoate2 benzoate3
SUL1    7.581312 7.394985 7.412040 2.1633230 2.05412373 1.9169226 0.004793318
+
PTC4 0.5391444 0.5793445 0.5597744  0.2543546  0.2539317  0.2202997
YMR244W 2.985682 2.975530 3.054001 0.3364722 0.33647224 0.1823216 0.188582576
+
GDH3 0.2480624 0.2373752 0.1911501 -0.3697303 -0.2982495 -0.3616723
DIP5    6.943991 7.147795 7.296955 0.6931472 0.09531018 0.5306283 0.253995075
+
AGA2 0.6735964 0.7860222 0.7222314  1.4807101  1.4885581  1.3976753
YLR460C 5.620401 5.801212 5.502482 3.2425924 3.48431229 3.3843903 0.307639012
+
CWP2 1.4723713 1.4582596 1.3802390  2.3759288  2.2504247  2.2710695
HXT4    2.821379 3.049273 2.772589 7.7893717 8.24446541 8.3041980 0.573813502
+
LSP1 0.7668296 0.8336119 0.7643181  1.3295121  1.2744859  1.2986457
 +
              pb pb.adjusted
 +
PTC4 4.054985e-05  0.2594379
 +
GDH3 5.967727e-05  0.3818152
 +
AGA2 8.244790e-05  0.5275016
 +
CWP2 1.041416e-04  0.6662979
 +
LSP1 1.095217e-04  0.7007201
 
</pre>
 
</pre>
  
Do the same procedure for benzoate p-values and '''report''' the result (in your table, report both p-values and expression levels for bezoate, not acetate). '''Comment''' the results for both acids.
+
Do the same procedure for acetate p-values and '''report''' the result (in your table, report both p-values and expression levels for acetate, not bezoate). '''Comment''' on the results for both acids.
  
 
===Task D: volcano plot, test on data generated from null hypothesis===
 
===Task D: volcano plot, test on data generated from null hypothesis===
  
Draw a [https://en.wikipedia.org/wiki/Volcano_plot_(statistics) volcano plot] for the acetate data
+
Draw a [https://en.wikipedia.org/wiki/Volcano_plot_(statistics) volcano plot] for the acetate data.
* The x-axis of this plot is the difference between the mean of reference and the mean of acetate. You can compute row means of a matrix by <tt>rowMeans</tt>.
+
* The x-axis of this plot is the difference between the mean of control and the mean of acetate. You can compute row means of a matrix by <tt>rowMeans</tt>.
* The y-axis is -log10 of the p-value (use the p-values before multiple testing correction)
+
* The y-axis is -log10 of the p-value (use the p-values before multiple testing correction).
 
* You can quickly see the genes that have low p-values (high on y-axis) and also big difference in the mean expression between the two conditions (far from 0 on x-axis). You can also see if acetate increases or decreases the expression of these genes.
 
* You can quickly see the genes that have low p-values (high on y-axis) and also big difference in the mean expression between the two conditions (far from 0 on x-axis). You can also see if acetate increases or decreases the expression of these genes.
  
Now create a simulated dataset sharing some features of the real data but observing the null hypothesis that the mean of reference and acetate are the same for each gene
+
Now create a simulated dataset sharing some features of the real data but observing the null hypothesis that the mean of control and acetate are the same for each gene.
 
* Compute vector ''m'' of means for columns 1:6 from matrix ''a''
 
* Compute vector ''m'' of means for columns 1:6 from matrix ''a''
* Compute vectors ''sr'' and ''sa'' of standard deviations for reference columns and for acetate columns respectively. You can compute standard deviation for each row of a matrix by <tt>apply(some.matrix, 1, sd)</tt>
+
* Compute vectors ''sc'' and ''sa'' of standard deviations for control columns and for acetate columns respectively. You can compute standard deviation for each row of a matrix by <tt>apply(some.matrix, 1, sd)</tt>.
* For each i in 1:6398, create three samples from the normal distribution with mean <tt>m[i]</tt> and standard deviation <tt>sr[i]</tt> and three samples with mean <tt>m[i]</tt> and deviation <tt>sa[i]</tt> (use the <tt>rnorm</tt> function)
+
* For each i in 1:6398, create three samples from the normal distribution with mean <tt>m[i]</tt> and standard deviation <tt>sc[i]</tt> and three samples with mean <tt>m[i]</tt> and deviation <tt>sa[i]</tt> (use the <tt>rnorm</tt> function).
* On the resulting matrix apply Welch's t-test and draw the volcano plot.  
+
* On the resulting matrix, apply Welch's t-test and draw the volcano plot.  
 
* How many random genes have p-value at most 0.01? Is it roughly what we would expect under the null hypothesis?
 
* How many random genes have p-value at most 0.01? Is it roughly what we would expect under the null hypothesis?
  
Draw a histogram of p-values from the real data (reference vs acetate) and from the random data (use function <tt>hist</tt>). '''Describe''' how they differ. Is it what you would expect?
+
Draw a histogram of p-values from the real data (control vs acetate) and from the random data (use function <tt>hist</tt>). '''Describe''' how they differ. Is it what you would expect?
  
 
<!-- NOTEX -->  
 
<!-- NOTEX -->  
 
'''Submit''' plots <tt>volcano-real.png</tt>, <tt>volcano-random.png</tt>, <tt>hist-real.png</tt>, <tt>hist-random.png</tt>
 
'''Submit''' plots <tt>volcano-real.png</tt>, <tt>volcano-random.png</tt>, <tt>hist-real.png</tt>, <tt>hist-random.png</tt>
(real for real expression data and random for generated data)
+
(real for real expression data and random for generated data).
 
<!-- /NOTEX -->
 
<!-- /NOTEX -->

Latest revision as of 15:30, 24 April 2023

See also the current and the previous lecture.

  • Do either tasks A,B,C (beginners) or B,C,D (more advanced). You can also do all four for bonus credit.
  • In your protocol write used R commands with brief comments on your approach.
  • Submit required plots with filenames as specified.
  • For each task also include results as required and a short discussion commenting the results/plots you have obtained. Is the value of interest increasing or decreasing with some parameter? Are the results as expected or surprising?
  • Outline of protocol is in /tasks/r2/protocol.txt

Task A: sign test

  • Consider a situation in which players played n games, out of which a fraction of q were won by A (the example in the lecture corresponds to q=0.6 and n=10).
  • Compute a table of p-values for combinations of n=10,20,...,90,100 and q=0.6, 0.7, 0.8, 0.9.
  • Plot the table using matplot (n is x-axis, one line for each value of q).
  • Submit the plot in sign.png.
  • Discuss the values you see in the plot / table.

Outline of the code:

# create vector rows with values 10,20,...,100
rows = (1:10) * 10
# create vector columns with required values of q
columns = c(0.6, 0.7, 0.8, 0.9)
# create empty matrix of pvalues 
pvalues = matrix(0, length(rows), length(columns))
# TODO: fill in matrix pvalues using binom.test

# set names of rows and columns
rownames(pvalues) = rows
colnames(pvalues) = columns
# careful: pvalues[10,] is now 10th row, i.e. value for n=100, 
#          pvalues["10",] is the first row, i.e. value for n=10

# check that for n=10 and q=0.6 you get p-value 0.3769531
pvalues["10","0.6"]

# create x-axis matrix (as in HWr1, part D)
x=matrix(rep(rows, length(columns)), nrow=length(rows))
# matplot command
png("sign.png")
matplot(x, pvalues, type="l", col=c(1:length(columns)), lty=1)
legend("topright", legend=columns, col=c(1:length(columns)), lty=1)
dev.off()

Task B: Welch's t-test on microarray data

Run the code below which reads the microarray data and preprocesses them (the last time we worked with preprocessed data). We first transform it to log scale and then shift and scale values in each column so that median is 0 and sum of squares of values is 1. This makes values more comparable between experiments; in practice more elaborate normalization is often performed. In the rest, work with table a containing preprocessed data.

# read the input file
input = read.table("/tasks/r2/acids.tsv", header=TRUE, row.names=1)
# take logarithm of all the values in the table
input = log2(input)
# compute median of each column
med = apply(input, 2, median)
# shift and scale values
a = scale(input, center=med)

Columns 1,2,3 are control, columns 4,5,6 acetic acid, 7,8,9 benzoate, 10,11,12 propionate, and 13,14,15 sorbate.

Write a function my.test which will take as arguments table a and 2 lists of columns (e.g. 1:3 and 4:6) and will run for each row of the table Welch's t-test of the first set of columns versus the second set. It will return the resulting vector of p-values, one for each gene.

  • For example by calling pb <- my.test(a, 1:3, 7:9) we will compute p-values for differences between control and benzoate (computation may take some time)
  • The first 5 values of pb should be
> pb[1:5]
[1] 0.02358974 0.05503082 0.15354833 0.68060345 0.04637482
  • Run the test for all four acids.
  • Report for each acid how many genes were significant with p-value at most 0.01.
  • Report also how many genes are significant for both acetic and benzoate acids simultaneously (logical "and" is written as &).

Task C: multiple testing correction

Run the following snippet of code, which works on the vector of p-values pb obtained for benzoate in task B.

# adjusts vectors of p-values from tasks B for using Bonferroni correction
pb.adjusted = p.adjust(pb, method ="bonferroni")
# add both p-value columns pb and pb.adjusted to frame a
a <-  cbind(a, pb, pb.adjusted)
# create permutation ordered by pb.adjusted
ob = order(pb.adjusted)
# select from table five rows with the lowest pb.adjusted (using vector ob)
# and display columns containing control, benzoate and both original and adjusted p-value
a[ob[1:5],c(1:3,7:9,16,17)]

You should get an output like this:

      control1  control2  control3  benzoate1  benzoate2  benzoate3
PTC4 0.5391444 0.5793445 0.5597744  0.2543546  0.2539317  0.2202997
GDH3 0.2480624 0.2373752 0.1911501 -0.3697303 -0.2982495 -0.3616723
AGA2 0.6735964 0.7860222 0.7222314  1.4807101  1.4885581  1.3976753
CWP2 1.4723713 1.4582596 1.3802390  2.3759288  2.2504247  2.2710695
LSP1 0.7668296 0.8336119 0.7643181  1.3295121  1.2744859  1.2986457
               pb pb.adjusted
PTC4 4.054985e-05   0.2594379
GDH3 5.967727e-05   0.3818152
AGA2 8.244790e-05   0.5275016
CWP2 1.041416e-04   0.6662979
LSP1 1.095217e-04   0.7007201

Do the same procedure for acetate p-values and report the result (in your table, report both p-values and expression levels for acetate, not bezoate). Comment on the results for both acids.

Task D: volcano plot, test on data generated from null hypothesis

Draw a volcano plot for the acetate data.

  • The x-axis of this plot is the difference between the mean of control and the mean of acetate. You can compute row means of a matrix by rowMeans.
  • The y-axis is -log10 of the p-value (use the p-values before multiple testing correction).
  • You can quickly see the genes that have low p-values (high on y-axis) and also big difference in the mean expression between the two conditions (far from 0 on x-axis). You can also see if acetate increases or decreases the expression of these genes.

Now create a simulated dataset sharing some features of the real data but observing the null hypothesis that the mean of control and acetate are the same for each gene.

  • Compute vector m of means for columns 1:6 from matrix a
  • Compute vectors sc and sa of standard deviations for control columns and for acetate columns respectively. You can compute standard deviation for each row of a matrix by apply(some.matrix, 1, sd).
  • For each i in 1:6398, create three samples from the normal distribution with mean m[i] and standard deviation sc[i] and three samples with mean m[i] and deviation sa[i] (use the rnorm function).
  • On the resulting matrix, apply Welch's t-test and draw the volcano plot.
  • How many random genes have p-value at most 0.01? Is it roughly what we would expect under the null hypothesis?

Draw a histogram of p-values from the real data (control vs acetate) and from the random data (use function hist). Describe how they differ. Is it what you would expect?

Submit plots volcano-real.png, volcano-random.png, hist-real.png, hist-random.png (real for real expression data and random for generated data).