Vybrané partie z dátových štruktúr
2-INF-237, LS 2016/17
Streaming model: Rozdiel medzi revíziami
Z VPDS
(Vytvorená stránka „==Definition== * Input: stream of n elements * Goal: do one pass through the stream (or only a few passes), use a small memory (e.g. O(1) or O(log n)) and answer a spec...“) |
(→Count-Min sketch) |
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Riadok 13: | Riadok 13: | ||
* Example: if all values x are +1, we are simply counting frequencies of elements from {0,...,n-1} on input | * Example: if all values x are +1, we are simply counting frequencies of elements from {0,...,n-1} on input | ||
− | + | ==Count-Min sketch== | |
* Strict turnstile model | * Strict turnstile model |
Verzia zo dňa a času 17:27, 17. apríl 2017
Definition
- Input: stream of n elements
- Goal: do one pass through the stream (or only a few passes), use a small memory (e.g. O(1) or O(log n)) and answer a specific query about the stream
- Good for processing very fast streams, such as IP packets passing a router or measurements of a very low-powered device
- Not enough memory to store the whole stream, each item should be processed fast
- Strict turnstile model:
- underlying set {0,...,n-1}
- virtual vector F of length n initialized to zeroes
- stream consists of operations (j,x) meaning F[j]+=x
- At every point we have F[j]>=0 for each j
- Cash register model: all values x are positive
- Example: if all values x are +1, we are simply counting frequencies of elements from {0,...,n-1} on input
Count-Min sketch
- Strict turnstile model
- CM sketch with parameters epsilon and delta
- Array of counters A of depth and width
- Each row i of A has a hash function h_i from {0,...,n-1} to {0,...,w-1} (assume totally random, but a weaker assumption of pairwise independence sufficient for analysis)
- Update (j,x) does A[i,h_i(j)]+=x for all hash function i=0,...,n-1
- Query F[j]=? returns min_i A[i,h_i(j)]
- Let F be the correct answer, F' the answer returned
- Clearly F'>=F, because each A[i,k] may have contributions from other elements as well
- With probability at least 1-delta we have
- Proof:
- Let
- for a fixed row i: , because every other element k has probability 1/w to hash to column h_i(j) and thus it cntributes F[k]/w to
- By Markov inequality
- Probability that this happens in every row i is at most
- Memory does not depend on n
- Note: if we insert million elements and then delete all but 4 of them, in the final structure we are very likely to be able to identify the 4 remaining ones as M is only 4